CHM 1045
Dr. Michael Blaber
Name_________________________
SS #__________________________
Homework #3
Sr Sr2+
Cs Cs+
I I-
Se Se2-
SrCl2
CsCl
LiI
Li2Se
C4H10O + 6O2 -> 4CO2 + 5H2O
C 4 C 4
H 10 H 10
O 13 O 13
(8*12.01) + (18*1.008) + (1*15.999) = 96.08+18.14+15.999=130.22 amu
Group 2A, alkaline earth metals, or Be, Mg, Ca, Sr, Ba, Ra
Molecular weight: (6*12.01)+(12*1.08)+(6*15.999)=72.06+12.96+95.994=181.01amu
%C = 72.06/181.01 = .3981=39.81%
%H = 12.96/181.01 = .0716=7.16%
%O = 95.994/181.01 = 0.5303=53.03%