Stoichiometry: Chemical Formulas and Equations

Atomic and Molecular Weights


Atomic and Molecular Weights
The subscripts in chemical formulas, and the coefficients in chemical equations represent exact quantities.

H2O, for example, indicates that a water molecule comprises exactly two atoms of hydrogen and one atom of oxygen.

The following equation:

not only tells us that propane reacts with oxygen to produce carbon dioxide and water, but that 1 molecule of propane reacts with 5 molecules of oxygen to produce 3 molecules of carbon dioxide and 4 molecules of water.

Since counting individual atoms or molecules is a little difficult, quantitative aspects of chemistry rely on knowing the masses of the compounds involved.

The atomic mass scale

Atoms of different elements have different masses. Early work on the separation of water into its constituent elements (hydrogen and oxygen) indicated that 100 grams of water contained 11.1 grams of hydrogen and 88.9 grams of oxygen:

100 grams Water -> 11.1 grams Hydrogen + 88.9 grams Oxygen
 

Later, scientists discovered that water was composed of two atoms of hydrogen for each atom of oxygen. Therefore, in the above analysis, in the 11.1 grams of hydrogen there were twice as many atoms as in the 88.9 grams of oxygen. Therefore, an oxygen atom must weigh about 16 times as much as a hydrogen atom:

 
 

Hydrogen, the lightest element, was assigned a relative mass of '1', and the other elements were assigned 'atomic masses' relative to this value for hydrogen. Thus, oxygen was assigned an atomic mass of 16.

We now know that a hydrogen atom has a mass of 1.6735 x 10-24 grams, and that the oxygen atom has a mass of 2.6561 X 10-23 grams. As we saw earlier, it is convenient to use a reference unit when dealing with such small numbers: the atomic mass unit. The atomic mass unit (amu) was not standardized against hydrogen, but rather, against the 12C isotope of carbon (amu = 12).

Thus, the mass of the hydrogen atom (1H) is 1.0080 amu, and the mass of an oxygen atom (16O) is 15.995 amu. Once the masses of atoms were determined, the amu could be assigned an actual value:

1 amu = 1.66054 x 10-24 grams
conversely:
1 gram = 6.02214 x 1023 amu
Average atomic mass

Most elements occur in nature as a mixture of isotopes (i.e. populations of atoms with different numbers of neutrons, and therefore, mass). We can calculate the average atomic mass of an element by knowing the relative abundance of each isotope, as well as the mass of each isotope.

Example: Naturally occurring carbon is 98.892% 12C and 1.108% 13C. The mass of 12C is 12 amu, and that of 13C is 13.00335 amu. Therefore, the average atomic mass of carbon is:

(0.98892)*(12 amu) + (0.01108)*(13.00335 amu) = 12.011 amu
 

The average atomic mass of each element (in amu) is also referred to as its atomic weight. Values for the atomic weights of each of the elements are commonly listed in periodic tables.

Formula and Molecular Weights

The formula weight of a substance is the sum of the atomic weights of each atom in its chemical formula.

For example, water (H2O) has a formula weight of:

2*(1.0079 amu) + 1*(15.9994 amu) = 18.01528 amu
 

If a substance exists as discrete molecules (as with atoms that are chemically bonded together) then the chemical formula is the molecular formula, and the formula weight is the molecular weight. For example, carbon, hydrogen and oxygen can chemically bond to form a molecule of the sugar glucose with the chemical and molecular formula of C6H12O6. The formula weight and the molecular weight of glucose is thus:

 
6*(12 amu) + 12*(1.00794 amu) + 6*(15.9994 amu)
= 180.0 amu
 

Ionic substances are not chemically bonded and do not exist as discrete molecules. However, they do associate in discrete ratios of ions. Thus, we can describe their formula weights, but not their molecular weights. Table salt (NaCl), for example, has a formula weight of:

23.0 amu + 35.5 amu
= 58.5 amu
 

Percentage composition from formulas

In some types of analyses of it is important to know the percentage by mass of each type of element in a compound. Take for example methane:

CH4
Formula and molecular weight: 1*(12.011 amu) + 4*(1.008) = 16.043 amu
%C = 1*(12.011 amu)/16.043 amu = 0.749 = 74.9%
%H = 4*(1.008 amu)/16.043 amu = 0.251 = 25.1%


1996 Michael Blaber